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Jan 24, 2024 · My thought was that was a vector space and a subspace with an uncountably infinite index. I then confused index and dimension instead of building a correct countere^Oct 13, 2008 · If W is a vector space itself, with the same vector space operations as V has, then it is a subspace of V. To use this definition, we dont have to prove that all t^Mar 4, 2008 · So Im considering dimensions of real vector spaces. I found myself thinking about the following: So for the vector space R2 there are the following possible subspac